-3/(x+1)=-2/(x+2)

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Solution for -3/(x+1)=-2/(x+2) equation: 



-3/(x+1)=-2/(x+2)

We move all terms to the left:

-3/(x+1)-(-2/(x+2))=0



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R





Domain of the equation: (x+2))!=0

x∈R



We calculate fractions


(-3x)/((x+1)*(x+2)))+(-(-2*(x+1))/((x+1)*(x+2)))=0



We calculate terms in parentheses: -(-2*(x+1))/((x+1)*(x+2))), so:

-2*(x+1))/((x+1)*(x+2))

We multiply all the terms by the denominator


-2*(x+1))

We multiply parentheses

-2x-

We add all the numbers together, and all the variables

-2x

Back to the equation:

-(-2x)



We get rid of parentheses

(-3x)/((x+1)*(x+2)))+(+2x=0

We multiply all the terms by the denominator


(-3x)+2x*((x+1)*(x+2)))+(=0

We get rid of parentheses

-3x+2x*((x+1)*(x+2)))+(=0

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