3(2z-3)-3(2-3z)=3

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Solution for 3(2z-3)-3(2-3z)=3 equation: 



3(2z-3)-3(2-3z)=3

We move all terms to the left:

3(2z-3)-3(2-3z)-(3)=0

We add all the numbers together, and all the variables

3(2z-3)-3(-3z+2)-3=0

We multiply parentheses

6z+9z-9-6-3=0

We add all the numbers together, and all the variables

15z-18=0

We move all terms containing z to the left, all other terms to the right

15z=18

z=18/15

z=1+1/5

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