3(6c+1)-13=16c+4

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Solution for 3(6c+1)-13=16c+4 equation: 



3(6c+1)-13=16c+4

We move all terms to the left:

3(6c+1)-13-(16c+4)=0

We multiply parentheses

18c-(16c+4)+3-13=0

We get rid of parentheses

18c-16c-4+3-13=0

We add all the numbers together, and all the variables

2c-14=0

We move all terms containing c to the left, all other terms to the right

2c=14

c=14/2

c=7

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