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3(2z+25)-2(z-1=7/8
We move all terms to the left:
3(2z+25)-2(z-1-(7/8)=0
We add all the numbers together, and all the variables
3(2z+25)-2(z-1-(+7/8)=0
We multiply parentheses
6z-2(z-1-(+7/8)+75=0
We multiply all the terms by the denominator
6z*8)+75-2(z-1-(+7=0
We add all the numbers together, and all the variables
6z*8)+75-2(z=0
Wy multiply elements
48z^2=0
a = 48; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·48·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$z=\frac{-b}{2a}=\frac{0}{96}=0$
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