3(2z+1)=39

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Solution for 3(2z+1)=39 equation: 



3(2z+1)=39

We move all terms to the left:

3(2z+1)-(39)=0

We multiply parentheses

6z+3-39=0

We add all the numbers together, and all the variables

6z-36=0

We move all terms containing z to the left, all other terms to the right

6z=36

z=36/6

z=6

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