3(2z+1)-5-z=3(1+z)=

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Solution for 3(2z+1)-5-z=3(1+z)= equation: 



3(2z+1)-5-z=3(1+z)=

We move all terms to the left:

3(2z+1)-5-z-(3(1+z))=0

We add all the numbers together, and all the variables

3(2z+1)-z-(3(z+1))-5=0

We add all the numbers together, and all the variables

-1z+3(2z+1)-(3(z+1))-5=0

We multiply parentheses

-1z+6z-(3(z+1))+3-5=0



We calculate terms in parentheses: -(3(z+1)), so:

3(z+1)

We multiply parentheses

3z+3

Back to the equation:

-(3z+3)



We add all the numbers together, and all the variables

5z-(3z+3)-2=0

We get rid of parentheses

5z-3z-3-2=0

We add all the numbers together, and all the variables

2z-5=0

We move all terms containing z to the left, all other terms to the right

2z=5

z=5/2

z=2+1/2

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