-2(3y-6)-7=16

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Solution for -2(3y-6)-7=16 equation: 



-2(3y-6)-7=16

We move all terms to the left:

-2(3y-6)-7-(16)=0

We add all the numbers together, and all the variables

-2(3y-6)-23=0

We multiply parentheses

-6y+12-23=0

We add all the numbers together, and all the variables

-6y-11=0

We move all terms containing y to the left, all other terms to the right

-6y=11

y=11/-6

y=-1+5/6

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