3(2y-4)=y+8

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Solution for 3(2y-4)=y+8 equation: 



3(2y-4)=y+8

We move all terms to the left:

3(2y-4)-(y+8)=0

We multiply parentheses

6y-(y+8)-12=0

We get rid of parentheses

6y-y-8-12=0

We add all the numbers together, and all the variables

5y-20=0

We move all terms containing y to the left, all other terms to the right

5y=20

y=20/5

y=4

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