(7x+1)+38=(10x+9)

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Solution for (7x+1)+38=(10x+9) equation: 



(7x+1)+38=(10x+9)

We move all terms to the left:

(7x+1)+38-((10x+9))=0

We get rid of parentheses

7x-((10x+9))+1+38=0



We calculate terms in parentheses: -((10x+9)), so:

(10x+9)

We get rid of parentheses

10x+9

Back to the equation:

-(10x+9)



We add all the numbers together, and all the variables

7x-(10x+9)+39=0

We get rid of parentheses

7x-10x-9+39=0

We add all the numbers together, and all the variables

-3x+30=0

We move all terms containing x to the left, all other terms to the right

-3x=-30

x=-30/-3

x=+10

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