3(2y-4)-y=7

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Solution for 3(2y-4)-y=7 equation: 



3(2y-4)-y=7

We move all terms to the left:

3(2y-4)-y-(7)=0

We add all the numbers together, and all the variables

-1y+3(2y-4)-7=0

We multiply parentheses

-1y+6y-12-7=0

We add all the numbers together, and all the variables

5y-19=0

We move all terms containing y to the left, all other terms to the right

5y=19

y=19/5

y=3+4/5

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