3(2y-3)=2y+12

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Solution for 3(2y-3)=2y+12 equation: 



3(2y-3)=2y+12

We move all terms to the left:

3(2y-3)-(2y+12)=0

We multiply parentheses

6y-(2y+12)-9=0

We get rid of parentheses

6y-2y-12-9=0

We add all the numbers together, and all the variables

4y-21=0

We move all terms containing y to the left, all other terms to the right

4y=21

y=21/4

y=5+1/4

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