40=x(10-2x)(8-2x

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Solution for 40=x(10-2x)(8-2x equation: 



40=x(10-2x)(8-2x

We move all terms to the left:

40-(x(10-2x)(8-2x)=0

We add all the numbers together, and all the variables

-(x(-2x+10)(-2x+8)+40=0

We multiply parentheses ..

-(x(+4x^2-16x-20x+80)+40=0

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