3(2y+3)=-2(5y-2)

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Solution for 3(2y+3)=-2(5y-2) equation: 



3(2y+3)=-2(5y-2)

We move all terms to the left:

3(2y+3)-(-2(5y-2))=0

We multiply parentheses

6y-(-2(5y-2))+9=0



We calculate terms in parentheses: -(-2(5y-2)), so:

-2(5y-2)

We multiply parentheses

-10y+4

Back to the equation:

-(-10y+4)



We get rid of parentheses

6y+10y-4+9=0

We add all the numbers together, and all the variables

16y+5=0

We move all terms containing y to the left, all other terms to the right

16y=-5

y=-5/16

y=-5/16

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