(5y+2)-2(y-1)=7(y+3)

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Solution for (5y+2)-2(y-1)=7(y+3) equation: 



(5y+2)-2(y-1)=7(y+3)

We move all terms to the left:

(5y+2)-2(y-1)-(7(y+3))=0

We multiply parentheses

(5y+2)-2y-(7(y+3))+2=0

We get rid of parentheses

5y-2y-(7(y+3))+2+2=0



We calculate terms in parentheses: -(7(y+3)), so:

7(y+3)

We multiply parentheses

7y+21

Back to the equation:

-(7y+21)



We add all the numbers together, and all the variables

3y-(7y+21)+4=0

We get rid of parentheses

3y-7y-21+4=0

We add all the numbers together, and all the variables

-4y-17=0

We move all terms containing y to the left, all other terms to the right

-4y=17

y=17/-4

y=-4+1/4

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