3(2x-9)=33-2(x-2)

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Solution for 3(2x-9)=33-2(x-2) equation: 



3(2x-9)=33-2(x-2)

We move all terms to the left:

3(2x-9)-(33-2(x-2))=0

We multiply parentheses

6x-(33-2(x-2))-27=0



We calculate terms in parentheses: -(33-2(x-2)), so:

33-2(x-2)

determiningTheFunctionDomain
-2(x-2)+33

We multiply parentheses

-2x+4+33

We add all the numbers together, and all the variables

-2x+37

Back to the equation:

-(-2x+37)



We get rid of parentheses

6x+2x-37-27=0

We add all the numbers together, and all the variables

8x-64=0

We move all terms containing x to the left, all other terms to the right

8x=64

x=64/8

x=8

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