6+4x-18=2(2x+5)-22

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Solution for 6+4x-18=2(2x+5)-22 equation: 



6+4x-18=2(2x+5)-22

We move all terms to the left:

6+4x-18-(2(2x+5)-22)=0

We add all the numbers together, and all the variables

4x-(2(2x+5)-22)-12=0



We calculate terms in parentheses: -(2(2x+5)-22), so:

2(2x+5)-22

We multiply parentheses

4x+10-22

We add all the numbers together, and all the variables

4x-12

Back to the equation:

-(4x-12)



We get rid of parentheses

4x-4x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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