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3(2x-7)-x=5(x-1)+16(2x+3)
We move all terms to the left:
3(2x-7)-x-(5(x-1)+16(2x+3))=0
We add all the numbers together, and all the variables
-1x+3(2x-7)-(5(x-1)+16(2x+3))=0
We multiply parentheses
-1x+6x-(5(x-1)+16(2x+3))-21=0
We calculate terms in parentheses: -(5(x-1)+16(2x+3)), so:We add all the numbers together, and all the variables
5(x-1)+16(2x+3)
We multiply parentheses
5x+32x-5+48
We add all the numbers together, and all the variables
37x+43
Back to the equation:
-(37x+43)
5x-(37x+43)-21=0
We get rid of parentheses
5x-37x-43-21=0
We add all the numbers together, and all the variables
-32x-64=0
We move all terms containing x to the left, all other terms to the right
-32x=64
x=64/-32
x=-2
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