2(d+4)+3(d-2)=7

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Solution for 2(d+4)+3(d-2)=7 equation: 



2(d+4)+3(d-2)=7

We move all terms to the left:

2(d+4)+3(d-2)-(7)=0

We multiply parentheses

2d+3d+8-6-7=0

We add all the numbers together, and all the variables

5d-5=0

We move all terms containing d to the left, all other terms to the right

5d=5

d=5/5

d=1

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