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4.9x^2-51.62x+56=0
a = 4.9; b = -51.62; c = +56;
Δ = b2-4ac
Δ = -51.622-4·4.9·56
Δ = 1567.0244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51.62)-\sqrt{1567.0244}}{2*4.9}=\frac{51.62-\sqrt{1567.0244}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51.62)+\sqrt{1567.0244}}{2*4.9}=\frac{51.62+\sqrt{1567.0244}}{9.8} $
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