3(2x-6)+6(x-4)=-3(4-5x)+5x-20

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Solution for 3(2x-6)+6(x-4)=-3(4-5x)+5x-20 equation: 



3(2x-6)+6(x-4)=-3(4-5x)+5x-20

We move all terms to the left:

3(2x-6)+6(x-4)-(-3(4-5x)+5x-20)=0

We add all the numbers together, and all the variables

3(2x-6)+6(x-4)-(-3(-5x+4)+5x-20)=0

We multiply parentheses

6x+6x-(-3(-5x+4)+5x-20)-18-24=0



We calculate terms in parentheses: -(-3(-5x+4)+5x-20), so:

-3(-5x+4)+5x-20

We add all the numbers together, and all the variables

5x-3(-5x+4)-20

We multiply parentheses

5x+15x-12-20

We add all the numbers together, and all the variables

20x-32

Back to the equation:

-(20x-32)



We add all the numbers together, and all the variables

12x-(20x-32)-42=0

We get rid of parentheses

12x-20x+32-42=0

We add all the numbers together, and all the variables

-8x-10=0

We move all terms containing x to the left, all other terms to the right

-8x=10

x=10/-8

x=-1+1/4

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