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3/2x+x=485
We move all terms to the left:
3/2x+x-(485)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
x+3/2x-485=0
We multiply all the terms by the denominator
x*2x-485*2x+3=0
Wy multiply elements
2x^2-970x+3=0
a = 2; b = -970; c = +3;
Δ = b2-4ac
Δ = -9702-4·2·3
Δ = 940876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{940876}=\sqrt{4*235219}=\sqrt{4}*\sqrt{235219}=2\sqrt{235219}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-970)-2\sqrt{235219}}{2*2}=\frac{970-2\sqrt{235219}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-970)+2\sqrt{235219}}{2*2}=\frac{970+2\sqrt{235219}}{4} $
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