3(2x-5)=9(19-x)

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Solution for 3(2x-5)=9(19-x) equation: 



3(2x-5)=9(19-x)

We move all terms to the left:

3(2x-5)-(9(19-x))=0

We add all the numbers together, and all the variables

3(2x-5)-(9(-1x+19))=0

We multiply parentheses

6x-(9(-1x+19))-15=0



We calculate terms in parentheses: -(9(-1x+19)), so:

9(-1x+19)

We multiply parentheses

-9x+171

Back to the equation:

-(-9x+171)



We get rid of parentheses

6x+9x-171-15=0

We add all the numbers together, and all the variables

15x-186=0

We move all terms containing x to the left, all other terms to the right

15x=186

x=186/15

x=12+2/5

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