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3(2x-5)=10x-12-4x
We move all terms to the left:
3(2x-5)-(10x-12-4x)=0
We add all the numbers together, and all the variables
3(2x-5)-(6x-12)=0
We multiply parentheses
6x-(6x-12)-15=0
We get rid of parentheses
6x-6x+12-15=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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