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3(2x-5)-4(3x+1)=10
We move all terms to the left:
3(2x-5)-4(3x+1)-(10)=0
We multiply parentheses
6x-12x-15-4-10=0
We add all the numbers together, and all the variables
-6x-29=0
We move all terms containing x to the left, all other terms to the right
-6x=29
x=29/-6
x=-4+5/6
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