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2(x-3)+9=3(x+1)+1
We move all terms to the left:
2(x-3)+9-(3(x+1)+1)=0
We multiply parentheses
2x-(3(x+1)+1)-6+9=0
We calculate terms in parentheses: -(3(x+1)+1), so:We add all the numbers together, and all the variables
3(x+1)+1
We multiply parentheses
3x+3+1
We add all the numbers together, and all the variables
3x+4
Back to the equation:
-(3x+4)
2x-(3x+4)+3=0
We get rid of parentheses
2x-3x-4+3=0
We add all the numbers together, and all the variables
-1x-1=0
We move all terms containing x to the left, all other terms to the right
-x=1
x=1/-1
x=-1
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