3(2x-5)-2=3(x-4)+1

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Solution for 3(2x-5)-2=3(x-4)+1 equation: 



3(2x-5)-2=3(x-4)+1

We move all terms to the left:

3(2x-5)-2-(3(x-4)+1)=0

We multiply parentheses

6x-(3(x-4)+1)-15-2=0



We calculate terms in parentheses: -(3(x-4)+1), so:

3(x-4)+1

We multiply parentheses

3x-12+1

We add all the numbers together, and all the variables

3x-11

Back to the equation:

-(3x-11)



We add all the numbers together, and all the variables

6x-(3x-11)-17=0

We get rid of parentheses

6x-3x+11-17=0

We add all the numbers together, and all the variables

3x-6=0

We move all terms containing x to the left, all other terms to the right

3x=6

x=6/3

x=2

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