x=1/5(x-3)+(2x-4)

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Solution for x=1/5(x-3)+(2x-4) equation: 



x=1/5(x-3)+(2x-4)

We move all terms to the left:

x-(1/5(x-3)+(2x-4))=0



Domain of the equation: 5(x-3)+(2x-4))!=0

x∈R



We multiply all the terms by the denominator


x*5(x-3)+(2x-4))-(1=0

Wy multiply elements

5x^2(x+(2x-4))-(1=0

We add all the numbers together, and all the variables

5x^2(x+(2x-4))=0

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