3(2x-5)+11=9x-22

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Solution for 3(2x-5)+11=9x-22 equation: 



3(2x-5)+11=9x-22

We move all terms to the left:

3(2x-5)+11-(9x-22)=0

We multiply parentheses

6x-(9x-22)-15+11=0

We get rid of parentheses

6x-9x+22-15+11=0

We add all the numbers together, and all the variables

-3x+18=0

We move all terms containing x to the left, all other terms to the right

-3x=-18

x=-18/-3

x=+6

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