5(3-7c)-5c=8(-2+5c)+1

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Solution for 5(3-7c)-5c=8(-2+5c)+1 equation: 



5(3-7c)-5c=8(-2+5c)+1

We move all terms to the left:

5(3-7c)-5c-(8(-2+5c)+1)=0

We add all the numbers together, and all the variables

5(-7c+3)-5c-(8(5c-2)+1)=0

We add all the numbers together, and all the variables

-5c+5(-7c+3)-(8(5c-2)+1)=0

We multiply parentheses

-5c-35c-(8(5c-2)+1)+15=0



We calculate terms in parentheses: -(8(5c-2)+1), so:

8(5c-2)+1

We multiply parentheses

40c-16+1

We add all the numbers together, and all the variables

40c-15

Back to the equation:

-(40c-15)



We add all the numbers together, and all the variables

-40c-(40c-15)+15=0

We get rid of parentheses

-40c-40c+15+15=0

We add all the numbers together, and all the variables

-80c+30=0

We move all terms containing c to the left, all other terms to the right

-80c=-30

c=-30/-80

c=3/8

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