3(2x-4)=4x+28

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Solution for 3(2x-4)=4x+28 equation: 



3(2x-4)=4x+28

We move all terms to the left:

3(2x-4)-(4x+28)=0

We multiply parentheses

6x-(4x+28)-12=0

We get rid of parentheses

6x-4x-28-12=0

We add all the numbers together, and all the variables

2x-40=0

We move all terms containing x to the left, all other terms to the right

2x=40

x=40/2

x=20

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