6(8-2z)=10z

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Solution for 6(8-2z)=10z equation: 



6(8-2z)=10z

We move all terms to the left:

6(8-2z)-(10z)=0

We add all the numbers together, and all the variables

6(-2z+8)-10z=0

We add all the numbers together, and all the variables

-10z+6(-2z+8)=0

We multiply parentheses

-10z-12z+48=0

We add all the numbers together, and all the variables

-22z+48=0

We move all terms containing z to the left, all other terms to the right

-22z=-48

z=-48/-22

z=2+2/11

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