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3(2x-4)=2(5x-20)
We move all terms to the left:
3(2x-4)-(2(5x-20))=0
We multiply parentheses
6x-(2(5x-20))-12=0
We calculate terms in parentheses: -(2(5x-20)), so:We get rid of parentheses
2(5x-20)
We multiply parentheses
10x-40
Back to the equation:
-(10x-40)
6x-10x+40-12=0
We add all the numbers together, and all the variables
-4x+28=0
We move all terms containing x to the left, all other terms to the right
-4x=-28
x=-28/-4
x=+7
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