3(2x-4)(x+8)=0

Solution for 3(2x-4)(x+8)=0 equation:

3(2x-4)(x+8)=0

We multiply parentheses ..

3(+2x^2+16x-4x-32)=0

We multiply parentheses

6x^2+48x-12x-96=0

We add all the numbers together, and all the variables

6x^2+36x-96=0

a = 6; b = 36; c = -96;
Δ = b2-4ac
Δ = 362-4·6·(-96)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-60}{2*6}=\frac{-96}{12}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+60}{2*6}=\frac{24}{12}
=2
$