3(2x-3)=2(6x-2)+1

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Solution for 3(2x-3)=2(6x-2)+1 equation: 



3(2x-3)=2(6x-2)+1

We move all terms to the left:

3(2x-3)-(2(6x-2)+1)=0

We multiply parentheses

6x-(2(6x-2)+1)-9=0



We calculate terms in parentheses: -(2(6x-2)+1), so:

2(6x-2)+1

We multiply parentheses

12x-4+1

We add all the numbers together, and all the variables

12x-3

Back to the equation:

-(12x-3)



We get rid of parentheses

6x-12x+3-9=0

We add all the numbers together, and all the variables

-6x-6=0

We move all terms containing x to the left, all other terms to the right

-6x=6

x=6/-6

x=-1

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