3(2x-3)2(-x+36)=103

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Solution for 3(2x-3)2(-x+36)=103 equation: 



3(2x-3)2(-x+36)=103

We move all terms to the left:

3(2x-3)2(-x+36)-(103)=0

We add all the numbers together, and all the variables

3(2x-3)2(-1x+36)-103=0

We move all terms containing x to the left, all other terms to the right

3(2x-3)2(-1x+36)=103

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