12(x-2)+3x=2(x+12)+10x

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Solution for 12(x-2)+3x=2(x+12)+10x equation: 



12(x-2)+3x=2(x+12)+10x

We move all terms to the left:

12(x-2)+3x-(2(x+12)+10x)=0

We add all the numbers together, and all the variables

3x+12(x-2)-(2(x+12)+10x)=0

We multiply parentheses

3x+12x-(2(x+12)+10x)-24=0



We calculate terms in parentheses: -(2(x+12)+10x), so:

2(x+12)+10x

We add all the numbers together, and all the variables

10x+2(x+12)

We multiply parentheses

10x+2x+24

We add all the numbers together, and all the variables

12x+24

Back to the equation:

-(12x+24)



We add all the numbers together, and all the variables

15x-(12x+24)-24=0

We get rid of parentheses

15x-12x-24-24=0

We add all the numbers together, and all the variables

3x-48=0

We move all terms containing x to the left, all other terms to the right

3x=48

x=48/3

x=16

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