3(2x-3)-7=9-3(4x-5)

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Solution for 3(2x-3)-7=9-3(4x-5) equation: 



3(2x-3)-7=9-3(4x-5)

We move all terms to the left:

3(2x-3)-7-(9-3(4x-5))=0

We multiply parentheses

6x-(9-3(4x-5))-9-7=0



We calculate terms in parentheses: -(9-3(4x-5)), so:

9-3(4x-5)

determiningTheFunctionDomain
-3(4x-5)+9

We multiply parentheses

-12x+15+9

We add all the numbers together, and all the variables

-12x+24

Back to the equation:

-(-12x+24)



We add all the numbers together, and all the variables

6x-(-12x+24)-16=0

We get rid of parentheses

6x+12x-24-16=0

We add all the numbers together, and all the variables

18x-40=0

We move all terms containing x to the left, all other terms to the right

18x=40

x=40/18

x=2+2/9

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