(X+3)(1/x+3+4)=(x+3)(21/x+3)

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Solution for (X+3)(1/x+3+4)=(x+3)(21/x+3) equation: 



(X+3)(1/X+3+4)=(X+3)(21/X+3)

We move all terms to the left:

(X+3)(1/X+3+4)-((X+3)(21/X+3))=0



Domain of the equation: X+3+4)!=0

We move all terms containing X to the left, all other terms to the right

X+4)!=-3

X∈R





Domain of the equation: X+3))!=0

X∈R



We add all the numbers together, and all the variables

(X+3)(1/X+7)-((X+3)(21/X+3))=0

We multiply parentheses ..

(+X^2+7X+3X+21)-((X+3)(21/X+3))=0

We multiply all the terms by the denominator


((+X^2+7X+3X+21))*X+3))-((X+3)(21=0

We add all the numbers together, and all the variables

((+X^2+7X+3X+21))*X+3))-((X=0

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