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3x+5=2/2x+3
We move all terms to the left:
3x+5-(2/2x+3)=0
Domain of the equation: 2x+3)!=0We get rid of parentheses
x∈R
3x-2/2x-3+5=0
We multiply all the terms by the denominator
3x*2x-3*2x+5*2x-2=0
Wy multiply elements
6x^2-6x+10x-2=0
We add all the numbers together, and all the variables
6x^2+4x-2=0
a = 6; b = 4; c = -2;
Δ = b2-4ac
Δ = 42-4·6·(-2)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8}{2*6}=\frac{-12}{12} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8}{2*6}=\frac{4}{12} =1/3 $
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