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3(2x-1)=5(x+1)+2
We move all terms to the left:
3(2x-1)-(5(x+1)+2)=0
We multiply parentheses
6x-(5(x+1)+2)-3=0
We calculate terms in parentheses: -(5(x+1)+2), so:We get rid of parentheses
5(x+1)+2
We multiply parentheses
5x+5+2
We add all the numbers together, and all the variables
5x+7
Back to the equation:
-(5x+7)
6x-5x-7-3=0
We add all the numbers together, and all the variables
x-10=0
We move all terms containing x to the left, all other terms to the right
x=10
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