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1/12(4x+9)=2/3x
We move all terms to the left:
1/12(4x+9)-(2/3x)=0
Domain of the equation: 12(4x+9)!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/12(4x+9)-(+2/3x)=0
We get rid of parentheses
1/12(4x+9)-2/3x=0
We calculate fractions
3x/(144x^2+324x)+(-24x4/(144x^2+324x)=0
We calculate terms in parentheses: +(-24x4/(144x^2+324x), so:
-24x4/(144x^2+324x
We multiply all the terms by the denominator
-24x4
We add all the numbers together, and all the variables
-24x^4
We do not support expression: x^4
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