3(2x-1)/4=4(x+2)/3-3

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Solution for 3(2x-1)/4=4(x+2)/3-3 equation: 



3(2x-1)/4=4(x+2)/3-3

We move all terms to the left:

3(2x-1)/4-(4(x+2)/3-3)=0

We calculate fractions


(18x-9)/()+(-(4(x+2)*4)/()=0



We calculate terms in parentheses: +(-(4(x+2)*4)/(), so:

-(4(x+2)*4)/(

We multiply all the terms by the denominator


-(4(x+2)*4)



We calculate terms in parentheses: -(4(x+2)*4), so:

4(x+2)*4

We multiply parentheses

16x+32

Back to the equation:

-(16x+32)



We get rid of parentheses

-16x-32

Back to the equation:

+(-16x-32)



We get rid of parentheses

(18x-9)/()-16x-32=0

We multiply all the terms by the denominator


(18x-9)-16x*()-32*()=0

We add all the numbers together, and all the variables

(18x-9)-16x*()=0

We get rid of parentheses

18x-16x*()-9=0

We move all terms containing x to the left, all other terms to the right

18x-16x*()=9

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