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(2x+1)(3x-7)=0
We multiply parentheses ..
(+6x^2-14x+3x-7)=0
We get rid of parentheses
6x^2-14x+3x-7=0
We add all the numbers together, and all the variables
6x^2-11x-7=0
a = 6; b = -11; c = -7;
Δ = b2-4ac
Δ = -112-4·6·(-7)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-17}{2*6}=\frac{-6}{12} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+17}{2*6}=\frac{28}{12} =2+1/3 $
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