3(2x-1)/4=1+2(x+2)/3

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Solution for 3(2x-1)/4=1+2(x+2)/3 equation: 



3(2x-1)/4=1+2(x+2)/3

We move all terms to the left:

3(2x-1)/4-(1+2(x+2)/3)=0

We calculate fractions


6x/()+(-(1+2(x+2)*4)/()=0



We calculate terms in parentheses: +(-(1+2(x+2)*4)/(), so:

-(1+2(x+2)*4)/(

We multiply all the terms by the denominator


-(1+2(x+2)*4)



We calculate terms in parentheses: -(1+2(x+2)*4), so:

1+2(x+2)*4

determiningTheFunctionDomain
2(x+2)*4+1

We multiply parentheses

8x+16+1

We add all the numbers together, and all the variables

8x+17

Back to the equation:

-(8x+17)



We get rid of parentheses

-8x-17

Back to the equation:

+(-8x-17)



We get rid of parentheses

6x/()-8x-17=0

We multiply all the terms by the denominator


6x-8x*()-17*()=0

We add all the numbers together, and all the variables

6x-8x*()=0

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