3(2x-1)+7x=2x+41

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Solution for 3(2x-1)+7x=2x+41 equation: 



3(2x-1)+7x=2x+41

We move all terms to the left:

3(2x-1)+7x-(2x+41)=0

We add all the numbers together, and all the variables

7x+3(2x-1)-(2x+41)=0

We multiply parentheses

7x+6x-(2x+41)-3=0

We get rid of parentheses

7x+6x-2x-41-3=0

We add all the numbers together, and all the variables

11x-44=0

We move all terms containing x to the left, all other terms to the right

11x=44

x=44/11

x=4

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