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45=1/3(3k-12)
We move all terms to the left:
45-(1/3(3k-12))=0
Domain of the equation: 3(3k-12))!=0We multiply all the terms by the denominator
k∈R
-(1+45*3(3k-12))=0
We calculate terms in parentheses: -(1+45*3(3k-12)), so:We add all the numbers together, and all the variables
1+45*3(3k-12)
determiningTheFunctionDomain 45*3(3k-12)+1
Wy multiply elements
135k(3+1
Back to the equation:
-(135k(3+1)
-(135k4=0
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