3(2x-1)+7=6x-3-2(2x-4x)

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Solution for 3(2x-1)+7=6x-3-2(2x-4x) equation: 



3(2x-1)+7=6x-3-2(2x-4x)

We move all terms to the left:

3(2x-1)+7-(6x-3-2(2x-4x))=0

We add all the numbers together, and all the variables

3(2x-1)-(6x-3-2(-2x))+7=0

We multiply parentheses

6x-(6x-3-2(-2x))-3+7=0



We calculate terms in parentheses: -(6x-3-2(-2x)), so:

6x-3-2(-2x)

determiningTheFunctionDomain
6x-2(-2x)-3

We multiply parentheses

6x+4x-3

We add all the numbers together, and all the variables

10x-3

Back to the equation:

-(10x-3)



We add all the numbers together, and all the variables

6x-(10x-3)+4=0

We get rid of parentheses

6x-10x+3+4=0

We add all the numbers together, and all the variables

-4x+7=0

We move all terms containing x to the left, all other terms to the right

-4x=-7

x=-7/-4

x=1+3/4

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