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3(2x-1)+7=6x-3-2(2x-4x
We move all terms to the left:
3(2x-1)+7-(6x-3-2(2x-4x)=0
We add all the numbers together, and all the variables
3(2x-1)-(6x-3-2(-2x)+7=0
We multiply parentheses
6x-(6x-3-2(-2x)+7-3=0
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