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3(2x+5)=5(1x+3)
We move all terms to the left:
3(2x+5)-(5(1x+3))=0
We add all the numbers together, and all the variables
3(2x+5)-(5(x+3))=0
We multiply parentheses
6x-(5(x+3))+15=0
We calculate terms in parentheses: -(5(x+3)), so:We get rid of parentheses
5(x+3)
We multiply parentheses
5x+15
Back to the equation:
-(5x+15)
6x-5x-15+15=0
We add all the numbers together, and all the variables
x=0
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