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3(2x+4)-3=2x(-5x-4)
We move all terms to the left:
3(2x+4)-3-(2x(-5x-4))=0
We multiply parentheses
6x-(2x(-5x-4))+12-3=0
We calculate terms in parentheses: -(2x(-5x-4)), so:We add all the numbers together, and all the variables
2x(-5x-4)
We multiply parentheses
-10x^2-8x
Back to the equation:
-(-10x^2-8x)
-(-10x^2-8x)+6x+9=0
We get rid of parentheses
10x^2+8x+6x+9=0
We add all the numbers together, and all the variables
10x^2+14x+9=0
a = 10; b = 14; c = +9;
Δ = b2-4ac
Δ = 142-4·10·9
Δ = -164
Delta is less than zero, so there is no solution for the equation
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